Calculus I › Applications of derivatives › full formula sheet

f″ > 0 ⇒ concave up  ·  f″ < 0 ⇒ concave down

Concavity

The second derivative reads the curve’s bend — smile or frown.

Concave up (∪, a smile — holds water) vs. concave down (∩, a frown — spills water). Bend is independent of uphill/downhill.

Before this lesson: Higher-order derivatives

Where it comes from

The problem: where does f(x) = x³ − 3x bend upward, and where downward? The naive guess — “concave up means increasing” — confuses bend with direction. Exhibit A, f(x) = −x² on (−∞, 0):

f′(x) = −2x
>
0  for x < 0
Increasing there — climbing…
f″(x) = −2
<
0  everywhere
…but bending downward the whole time (∩). Direction (f′) and bend (f″) are independent dials.

The right intuition: read the slopes left to right. On a smile ∪, slopes go −, 0, + — increasing. On a frown ∩, slopes go +, 0, − — decreasing. And “f′ increasing” is exactly what f″ > 0 says. That is the whole dictionary:

f″ > 0  ⇒  slopes increasing  ⇒  ∪ smile  ·  f″ < 0  ⇒  slopes decreasing  ⇒  ∩ frownSay it: the second derivative of f positive means the slopes are climbing, so the curve cups upward like a smile; negative means the slopes are falling, so it frowns

Before reading on: the slopes of f keep increasing as x grows. Does the graph cup upward or downward? Draw three tangent segments and see.

Derivation

Apply the increasing/decreasing theorem — not to f, but to f′.

f″ > 0 on I
⇒
f′ increasing on I
Step 1 — reuse the last theorem. f″ is the derivative of f′. Positive derivative ⇒ increasing function — so the slopes grow left to right.
slopes − → 0 → +
⇒
curve bends upward ∪
Step 2 — increasing slopes are a smile. Tangent lines tilt up as you move right; the curve cups upward. Equivalently, tangents lie below the graph. ∎
f″ < 0 on I
⇒
f′ decreasing ⇒ bends downward ∩
Step 3 — the mirror. Slopes shrink (+, 0, −): the frown. Tangents lie above the graph. ∎

Why “holds water”? A concave-up cup ∪ can hold water; concave-down ∩ spills it. And since tangents sit below a smile, a concave-up function always lies above its tangent lines — which is exactly why linear approximation underestimates concave-up functions (remember √x? No — that one bends down. Try x²: tangent at 1 is 2x−1, and x² ≥ 2x−1 always ✓).

Before reading on: f(x) = x⁴ has f″(0) = 0. Is (0, 0) an inflection point? What extra check decides it?

How to use it

The procedure — a carbon copy of the increasing/decreasing chart, one derivative higher:

  1. Compute f″.
  2. Find where f″ = 0 or is undefined (with f defined) — candidates where the bend might change.
  3. Split the domain at those points into intervals.
  4. Test the sign of f″ on each interval.
  5. Conclude: f″ > 0 ⇒ concave up; f″ < 0 ⇒ concave down — interval by interval.

Bend ≠ direction ≠ height

Three independent dials: f says where the graph is, f′ says which way it tilts, f″ says how it bends. All four combos exist — x² on (−∞, 0) is concave up and decreasing.

When to reach for it

Curve sketching (the bend completes the picture), finding inflection points (next page — where the bend flips), and the second derivative test (classifying maxima/minima by bend).

Common mistake: “f is positive there, so concave up.” Height is f’s business; bend is f″’s. sin x is positive on (0, π) yet concave down there.

Worked examples

Four bends, easiest first. In each one, read every step — the why of each move is the lesson.

Example 1 — the basic move: f(x) = x³

  1. Differentiate twice. f′(x) = 3x², f″(x) = 6x.
  2. Candidates. f″ = 0 at x = 0.
  3. Signs. 6x < 0 for x < 0; > 0 for x > 0.
  4. Conclude. Concave down on (−∞, 0), concave up on (0, ∞). (The cube bends down, flattens, bends up — an S.)
Common mistake: stopping at “f″(0) = 0” as if that were the answer. The zero only splits intervals — the signs on each side are the answer.
Your turn: f(x) = −x³ — where is it concave up / down?

Answer: Concave up on (−∞, 0); concave down on (0, ∞).

f″(x) = −6x: > 0 for x < 0 (up), < 0 for x > 0 (down) ✓.

Example 2 — flat but still up: f(x) = x4

  1. Differentiate twice. f′(x) = 4x³, f″(x) = 12x².
  2. Candidates. f″ = 0 at x = 0.
  3. Signs. 12x² ≥ 0 everywhere — and > 0 except at 0 itself.
  4. Conclude. Concave up on (−∞, 0) and on (0, ∞) — hence concave up everywhere. A zero of f″ with no sign change changes nothing.
Common mistake: “f″(0) = 0, so x = 0 is an inflection point.” No sign change, no inflection — the bend never flips. (Inflection points are next page.)
Your turn: f(x) = ex — concavity?

Answer: Concave up everywhere.

f″(x) = ex > 0 for all x — no candidates, no flips.

Example 3 — with a domain break: f(x) = 1/x

  1. Differentiate twice. f′(x) = −x−2, f″(x) = 2x−3 = 2/x³.
  2. Candidates. f″ is never 0; undefined at x = 0 — but f is undefined there too, so it’s a domain break, not a candidate.
  3. Signs. 2/x³ < 0 for x < 0 (negative denominator); > 0 for x > 0.
  4. Conclude. Concave down on (−∞, 0), concave up on (0, ∞) — separately, never glued.
Common mistake: claiming the concavity “changes at x = 0, so 0 is an inflection point.” Inflection points must be on the graph — f(0) doesn’t exist, so there’s no point there at all.
Your turn: f(x) = ln x (x > 0) — concavity?

Answer: Concave down on (0, ∞).

f′(x) = 1/x, f″(x) = −1/x² < 0 for every x > 0 ✓.

Example 4 — trigonometry: f(x) = sin x on [0, 2π]

  1. Differentiate twice. f′(x) = cos x, f″(x) = −sin x.
  2. Candidates. −sin x = 0 at x = 0, π, 2π.
  3. Signs. On (0, π): sin x > 0 → f″ < 0. On (π, 2π): sin x < 0 → f″ > 0.
  4. Conclude. Concave down on (0, π) (the arch ∩), concave up on (π, 2π) (the bowl ∪).
Common mistake: “sin is positive on (0, π), so concave up there.” That reads f’s sign, not f″’s — the arch is positive and frowning (∩) the whole way.
Your turn: f(x) = cos x on [0, 2π] — concavity intervals?

Answer: Concave up on (π/2, 3π/2); concave down on (0, π/2) and (3π/2, 2π).

f″(x) = −cos x > 0 exactly when cos x < 0, i.e. on (π/2, 3π/2) ✓.

Memorization tips

  • Smile ∪ = up = f″ > 0. Draw the smile next to the formula until it’s automatic.
  • Holds water / spills water: ∪ holds, ∩ spills. Say which while pointing at the graph.
  • Slopes increasing: read tangent tilts left to right — −, 0, + is a smile. That image is the proof.
  • Three dials: f = where, f′ = which way, f″ = how bent. Quiz yourself: “x² on (−∞, 0): up or down? increasing or decreasing?” (Up, decreasing.)
  • Same chart, one derivative higher: the procedure is identical to increasing/decreasing — just applied to f″.
  • Zero splits, sign decides: f″ = 0 only fences intervals; the sign on each side is the answer.

Final challenge

Five mixed questions — basics, applications, and the traps, all in one. Score 5/5 and concavity is yours.

← Back to the Calculus I formula sheet

How to learn a formula here

  1. Read each section in order — every section ends with a short quiz. Take it before moving on; the questions test exactly what you just read.
  2. Work the examples with the answers covered, then uncover one step at a time and compare.
  3. Finish with the final challenge — five mixed questions including the classic traps.
  4. Retake what you miss — every quiz reshuffles each attempt, and every answer explains itself.

Frequently asked questions

What is concavity?

Concavity is which way a curve bends: concave up (∪, like a smile — holds water) where f″ > 0, concave down (∩, like a frown) where f″ < 0.

Does concave up mean increasing?

No — bend and direction are independent. f(x) = x² is concave up everywhere but decreasing on (−∞, 0). Concavity reads the bend (f″); increasing reads the slope (f′).

Why does f″ > 0 mean concave up?

f″ > 0 means f′ is increasing — slopes grow left to right (−, 0, +). Slopes increasing through zero is exactly the smile shape ∪, bending upward.

What does f″ = 0 tell you about concavity?

By itself, nothing — it’s a candidate where concavity might change. f(x) = x4 has f″(0) = 0 but stays concave up; only a sign change of f″ marks a real bend change (an inflection point).

Where do tangent lines sit relative to the curve?

On a concave-up stretch, tangent lines lie below the curve (the smile sits above its tangents); on concave-down, tangents lie above. That’s why concave-up functions lie above their linear approximations.

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