Calculus I › Limits › full formula sheet

limx→a f(x) = ±∞  ⇒  vertical asymptote x = a

Infinite limits

When the function grows without bound near a point — and why the sign decides everything.

On this page “= ∞” is shorthand, not an equation: it describes how the limit fails to exist (by growing without bound). The two-sided infinite limit exists only if both sides agree in sign.

Notation in this lesson

limx→a f(x) = ±∞
f grows without bound near a — the values explode
x = a
vertical asymptote — the line the graph hugs
M
any large bound: f(x) exceeds every M near a
δ
how close x must stay to a to force f(x) > M

Where it comes from

Infinite limits are born where the quotient law dies: numerator heading somewhere nonzero, denominator heading to zero. The function doesn’t approach a number — it grows without bound, and we write lim = ±infinity as precise shorthand for that behavior.

Before reading on: 1/0 is undefined — so what could “limx→0 1/x = ∞” possibly mean?
lim(x→a) f(x) = +infinity means: f(x) exceeds every bound near avertical asymptote x = aSay it: the limit as x approaches a of f of x equals positive infinity

The naive move is “1/0 = infinity” — wrong twice:

lim(x→0+) 1/x = +infinity
vs.
lim(x→0−) 1/x = −infinity
Death 1: the sign. 1/0 is meaningless, and the sides tell opposite stories. “Infinity” without a sign — and without a side — says nothing.
infinity − infinity
=
???
Death 2: infinity isn’t a number. lim(x→0+)(1/x² − 1/x) = +infinity (it equals (1−x)/x² → +infinity), but “infinity minus infinity” as arithmetic is indeterminate — it can give anything.

The intuition: a nonzero numerator over a vanishing denominator means the ratio’s magnitude explodes; the signs of numerator and denominator decide whether it explodes upward or downward. The derivation makes “grows without bound” rigorous with M playing epsilon’s role.

Derivation

The definition mirrors epsilon-delta, with a bound M replacing epsilon. Then we prove lim(x→0) 1/x² = +infinity as the model argument.

lim(x→a) f = +infinity
⇔
∀M > 0, ∃δ > 0: 0 < |x−a| < δ ⇒ f(x) > M
Step 1 — the definition. “No matter how large a bound M you name, f(x) exceeds it near a.” Compare: epsilon-delta says f stays within epsilon; M-delta says f escapes beyond M.
M > 0 given
⇒
take δ = 1/√M
Step 2 — choose δ from M. For lim(x→0) 1/x²: we need 1/x² > M, i.e. x² < 1/M, i.e. |x| < 1/√M. So this δ works.
0 < |x| < δ
⇒
1/x² > M
Step 3 — verify. |x| < 1/√M ⇒ x² < 1/M ⇒ 1/x² > M. Since M was arbitrary, 1/x² exceeds every bound near 0. ∎

Key steps shown; the argument above is complete. For −infinity, negate: lim f = −infinity means lim(−f) = +infinity, i.e. f(x) < −M near a for every M > 0. And “the limit is infinity” never means the limit exists — it’s the precise description of one way a limit can fail.

How to use it

The procedure, every time:

  1. Identify the shape: numerator → nonzero L, denominator → 0. That’s the infinite-limit signature (the quotient law is off).
  2. Go one-sided. Determine the sign from each side: sign(numerator) × sign(denominator). Even powers in the denominator give the same sign both sides; odd powers flip.
  3. Compare sides: both +infinity (or both −infinity) → two-sided infinite limit. Mixed → the two-sided limit DNE.
  4. Conclude the asymptote: x = a is a vertical asymptote if at least one one-sided limit is infinite.

Reading the sign fast

Near a, ask: is the numerator positive or negative? Is the denominator approaching 0 through positive or negative values? +/+ and −/− explode upward; +/− and −/+ explode downward. For (x+2)/(x−1)³ at x = 1: numerator → 3 > 0; denominator → 0+ from the right (+infinity), 0− from the left (−infinity).

Common mistake: “the limit is infinity” for 1/x at 0 without checking sides. The right says +infinity, the left says −infinity — the two-sided infinite limit does not exist.

Worked examples

Four problems, easiest first. In each one, read every step — the why of each move is the lesson.

Example 1 — both sides agree: lim(x→0) 1/x²

  1. Signature check: numerator → 1 (nonzero), denominator → 0. Infinite behavior.
  2. Signs: x² > 0 from both sides (even power) — 1/0+ on both sides.
  3. Conclude: +infinity (two-sided). Vertical asymptote x = 0.
Common mistake: none — even powers in the denominator are the friendly case. The odd-power version is next.
Your turn: limx→0 2/x² = ?

Answer: +∞.

Numerator → 2 (nonzero), denominator → 0+ from both sides (x² > 0). 2/0+ = +∞; vertical asymptote x = 0.

Example 2 — still agreeing: lim(x→2) 3/(x−2)²

  1. Signature: numerator → 3, denominator → 0.
  2. Signs: (x−2)² > 0 both sides; numerator positive. Both sides: 3/0+.
  3. Conclude: +infinity. Vertical asymptote x = 2.
Common mistake: shifting errors — the blowup is at x = 2 (where the denominator vanishes), not at x = 0. Always locate the zero of the denominator.
Your turn: limx→1 4/(x−1)² = ?

Answer: +∞.

Denominator → 0+ on both sides; numerator → 4. Both sides agree: +∞.

Before reading on: 1/x near 0 — do the left and right sides blow up the same way? Predict before you check.

Example 3 — sides disagree: lim(x→0) 1/x

  1. Right side: x → 0+: 1/0+ = +infinity.
  2. Left side: x → 0−: 1/0− = −infinity.
  3. Two-sided verdict: the sides disagree, so the two-sided limit DNE — even as an infinite limit. (x = 0 is still a vertical asymptote: one infinite side suffices.)
Common mistake: “lim(x→0) 1/x = infinity.” Which infinity? The sign matters, and here the two-sided statement is simply false.
Your turn: limx→0 1/x³ = ?

Answer: DNE (two-sided).

Right side: 1/0+ = +∞; left side: 1/0− = −∞. The sides disagree, so no two-sided limit — even as an infinite limit.

Example 4 — odd power flips: lim(x→1) (x+2)/(x−1)³

  1. Signature: numerator → 3 (nonzero), denominator → 0.
  2. Right side: (x−1)³ → 0+ (positive small cubed stays positive): 3/0+ = +infinity.
  3. Left side: (x−1)³ → 0−: 3/0− = −infinity.
  4. Verdict: two-sided limit DNE; vertical asymptote x = 1.
Common mistake: assuming the cube “doesn’t matter” and treating it like the squared version. Odd powers preserve the sign of the approach — always track it.
Your turn: limx→2 (x+1)/(x−2)³ = ?

Answer: DNE (two-sided).

Numerator → 3; right side 3/0+ = +∞, left side 3/0− = −∞. Vertical asymptote x = 2.

Memorization tips

  • Numerator nonzero + denominator zero = blowup: the signature. The quotient law bows out; one-sided analysis takes over.
  • Even powers agree, odd powers flip: (x−a)2n gives the same infinity both sides; (x−a)2n+1 gives opposite infinities.
  • Sign(numerator) × sign(denominator): the two-sign multiplication that decides +infinity vs −infinity. Do it explicitly every time.
  • “DNE” is still the honest two-sided verdict when the sides disagree — “infinity” describes how it fails, one side at a time.
  • One infinite side makes the asymptote: x = a is a vertical asymptote if either one-sided limit is infinite.
  • M replaces epsilon: the definition “for every bound M, f exceeds M near a” is the infinite analogue of epsilon-delta. Same architecture, unbounded conclusion.

Final challenge

Five mixed questions — basics, applications, and the traps, all in one. Score 5/5 and this law is yours.

← Back to the Calculus I formula sheet

How to learn a formula here

  1. Read each section in order — every section ends with a short quiz. Take it before moving on; the questions test exactly what you just read.
  2. Work the examples with the answers covered, then uncover one step at a time and compare.
  3. Finish with the final challenge — five mixed questions including the classic traps.
  4. Retake what you miss — every quiz reshuffles each attempt, and every answer explains itself.

Frequently asked questions

What does lim(x→a) f(x) = ∞ actually mean?

It's shorthand, not an equation: for every bound M > 0, f(x) exceeds M near a. It describes precisely HOW the limit fails to exist — by growing without bound.

Why is '1/0 = ∞' wrong?

1/0 is meaningless, and the sign depends on the side: lim(x→0⁺) 1/x = +∞ but lim(x→0⁻) 1/x = −∞. Always do a one-sided sign analysis instead.

When does the two-sided infinite limit exist?

Only when both one-sided limits are infinite with the SAME sign — e.g. lim(x→0) 1/x² = +∞. For 1/x the sides disagree, so the two-sided limit DNE.

How do I find the sign quickly?

Multiply sign(numerator) × sign(denominator) near a from each side. Even powers in the denominator give the same sign both sides; odd powers flip it.

Does an infinite limit mean there's a vertical asymptote?

Yes — x = a is a vertical asymptote if at least one one-sided limit is ±∞. Both sides need not agree.

More from the codex